题解 - 练70.1 验证子串

chiqingrui LV 6 @ 2024-7-24 16:54:32

这题挺水的。（嗯）首先定义；输入；仨if 判断： 1.a是b子串 2.b是a子串 3.都不是输出就行。（嗯）

#include<bits/stdc++.h>
using namespace std;
string a,b
int main(){
    cin>>a>>b;
    if(a.find(b)!=-1)
	    cout<<b<<" is substring of "<<a;
    }
    else if(b.find(a)!=-1){
        cout<<a<<" is substring of "<b;
    }
    else
        cout<<"No substring"<<endl;
    return o;
}

lubingyu @ 2024-7-24 16:58:43

有坑，注意避雷！！！
chenxuanrun @ 2024-7-24 17:01:58
```
太坑了
```

lubingyu @ 2024-9-8 9:27:49

正确代码：

#include<bits/stdc++.h>
using namespace std;
string a,b;
int main(){
    cin>>a>>b;
    if(a.find(b)!=-1)
	    cout<<b<<" is substring of "<<a;
    }
    else if(b.find(a)!=-1){
        cout<<a<<" is substring of "<<b;
    }
    else
        cout<<"No substring"<<endl;
    return 0;
}

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